Advent of Code 2016 solutions https://adventofcode.com/2016/
您最多选择25个主题 主题必须以字母或数字开头,可以包含连字符 (-),并且长度不得超过35个字符

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  1. #!/usr/bin/python3
  2. """Solution for day 20 of Advent of Code 2016.
  3. This solution first compresses the blacklist by merging overlapping sections, using functools.reduce and the merge
  4. function below. For example, [(0, 100), (50, 150)] becomes (0, 150). The blacklist is then inverted to become a
  5. whitelist, which gives both answers pretty easily.
  6. """
  7. import functools
  8. def merge(x, y):
  9. if y[0] <= x[-1][1] + 1:
  10. # This entry overlaps with the last one, combine them
  11. x[-1] = (x[-1][0], max(y[1], x[-1][1]))
  12. else:
  13. # New, non-overlapping entry, just append it to our list
  14. x.append(y)
  15. return x
  16. with open('data/20.txt', 'r') as file:
  17. ranges = sorted(list(map(lambda x: tuple(map(int, x.strip().split('-'))), file.readlines())))
  18. blacklist = functools.reduce(merge, ranges[1:], [ranges[0]])
  19. whitelist = []
  20. last = 0
  21. for pair in blacklist:
  22. if pair[0] > last:
  23. whitelist.append((last, pair[0] - 1))
  24. last = pair[1] + 1
  25. if last < 4294967295:
  26. whitelist.append((last, 4294967295))
  27. print("Part 1: %s" % whitelist[0][0])
  28. print("Part 2: %s" % sum(map(lambda p: 1 + p[1] - p[0], whitelist)))